From point P on level ground, the elevation angle of a tower’s top is 30°. If the tower is 100 m high, the distance of point P from the foot of the building is:_________?
A. 149 m
B. 156 m
C. 173 m
D. 200 m
C. 173 m
Let AB be the tower. Then, ∠APB = 30° and AB = 100 m, AB/AP = tan 30° = 1/√3 AP = (AB X √3)= 100√3 m. = (100 X 1.73) m = 173 m.