**A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is_____________?**

A. 48 runs

B. 52 runs

C. 55 runs

D. 60 runs

**A. 48 runs**

Let the average for 10 innings be x. Then,

(10x + 108)/11 = x + 6

= 11x + 66 = 10x + 108

= x = 42.

New average = (x + 6) = 48 runs